3.105 \(\int \frac {x (a+b \text {csch}^{-1}(c x))}{(d+e x^2)^2} \, dx\)

Optimal. Leaf size=139 \[ -\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {b c x \tan ^{-1}\left (\sqrt {-c^2 x^2-1}\right )}{2 d e \sqrt {-c^2 x^2}}+\frac {b c x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-c^2 x^2-1}}{\sqrt {c^2 d-e}}\right )}{2 d \sqrt {e} \sqrt {-c^2 x^2} \sqrt {c^2 d-e}} \]

[Out]

1/2*(-a-b*arccsch(c*x))/e/(e*x^2+d)+1/2*b*c*x*arctan((-c^2*x^2-1)^(1/2))/d/e/(-c^2*x^2)^(1/2)+1/2*b*c*x*arctan
h(e^(1/2)*(-c^2*x^2-1)^(1/2)/(c^2*d-e)^(1/2))/d/(c^2*d-e)^(1/2)/e^(1/2)/(-c^2*x^2)^(1/2)

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Rubi [A]  time = 0.15, antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {6300, 446, 86, 63, 205, 208} \[ -\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {b c x \tan ^{-1}\left (\sqrt {-c^2 x^2-1}\right )}{2 d e \sqrt {-c^2 x^2}}+\frac {b c x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-c^2 x^2-1}}{\sqrt {c^2 d-e}}\right )}{2 d \sqrt {e} \sqrt {-c^2 x^2} \sqrt {c^2 d-e}} \]

Antiderivative was successfully verified.

[In]

Int[(x*(a + b*ArcCsch[c*x]))/(d + e*x^2)^2,x]

[Out]

-(a + b*ArcCsch[c*x])/(2*e*(d + e*x^2)) + (b*c*x*ArcTan[Sqrt[-1 - c^2*x^2]])/(2*d*e*Sqrt[-(c^2*x^2)]) + (b*c*x
*ArcTanh[(Sqrt[e]*Sqrt[-1 - c^2*x^2])/Sqrt[c^2*d - e]])/(2*d*Sqrt[c^2*d - e]*Sqrt[e]*Sqrt[-(c^2*x^2)])

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 86

Int[((e_.) + (f_.)*(x_))^(p_)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), In
t[(e + f*x)^p/(a + b*x), x], x] - Dist[d/(b*c - a*d), Int[(e + f*x)^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d,
e, f, p}, x] &&  !IntegerQ[p]

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 6300

Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*(x_)*((d_.) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)^(p +
1)*(a + b*ArcCsch[c*x]))/(2*e*(p + 1)), x] - Dist[(b*c*x)/(2*e*(p + 1)*Sqrt[-(c^2*x^2)]), Int[(d + e*x^2)^(p
+ 1)/(x*Sqrt[-1 - c^2*x^2]), x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x \left (a+b \text {csch}^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx &=-\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {(b c x) \int \frac {1}{x \sqrt {-1-c^2 x^2} \left (d+e x^2\right )} \, dx}{2 e \sqrt {-c^2 x^2}}\\ &=-\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {(b c x) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {-1-c^2 x} (d+e x)} \, dx,x,x^2\right )}{4 e \sqrt {-c^2 x^2}}\\ &=-\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}-\frac {(b c x) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1-c^2 x} (d+e x)} \, dx,x,x^2\right )}{4 d \sqrt {-c^2 x^2}}+\frac {(b c x) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {-1-c^2 x}} \, dx,x,x^2\right )}{4 d e \sqrt {-c^2 x^2}}\\ &=-\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {(b x) \operatorname {Subst}\left (\int \frac {1}{d-\frac {e}{c^2}-\frac {e x^2}{c^2}} \, dx,x,\sqrt {-1-c^2 x^2}\right )}{2 c d \sqrt {-c^2 x^2}}-\frac {(b x) \operatorname {Subst}\left (\int \frac {1}{-\frac {1}{c^2}-\frac {x^2}{c^2}} \, dx,x,\sqrt {-1-c^2 x^2}\right )}{2 c d e \sqrt {-c^2 x^2}}\\ &=-\frac {a+b \text {csch}^{-1}(c x)}{2 e \left (d+e x^2\right )}+\frac {b c x \tan ^{-1}\left (\sqrt {-1-c^2 x^2}\right )}{2 d e \sqrt {-c^2 x^2}}+\frac {b c x \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {-1-c^2 x^2}}{\sqrt {c^2 d-e}}\right )}{2 d \sqrt {c^2 d-e} \sqrt {e} \sqrt {-c^2 x^2}}\\ \end {align*}

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Mathematica [C]  time = 0.79, size = 271, normalized size = 1.95 \[ -\frac {\frac {2 a}{d+e x^2}+\frac {b \sqrt {e} \log \left (-\frac {4 \left (c d \sqrt {e} x \left (c \sqrt {d}+i \sqrt {\frac {1}{c^2 x^2}+1} \sqrt {e-c^2 d}\right )+i d e\right )}{b \sqrt {e-c^2 d} \left (\sqrt {d}-i \sqrt {e} x\right )}\right )}{d \sqrt {e-c^2 d}}+\frac {b \sqrt {e} \log \left (\frac {4 i \left (d e+c d \sqrt {e} x \left (\sqrt {\frac {1}{c^2 x^2}+1} \sqrt {e-c^2 d}+i c \sqrt {d}\right )\right )}{b \sqrt {e-c^2 d} \left (\sqrt {d}+i \sqrt {e} x\right )}\right )}{d \sqrt {e-c^2 d}}+\frac {2 b \text {csch}^{-1}(c x)}{d+e x^2}-\frac {2 b \sinh ^{-1}\left (\frac {1}{c x}\right )}{d}}{4 e} \]

Antiderivative was successfully verified.

[In]

Integrate[(x*(a + b*ArcCsch[c*x]))/(d + e*x^2)^2,x]

[Out]

-1/4*((2*a)/(d + e*x^2) + (2*b*ArcCsch[c*x])/(d + e*x^2) - (2*b*ArcSinh[1/(c*x)])/d + (b*Sqrt[e]*Log[(-4*(I*d*
e + c*d*Sqrt[e]*(c*Sqrt[d] + I*Sqrt[-(c^2*d) + e]*Sqrt[1 + 1/(c^2*x^2)])*x))/(b*Sqrt[-(c^2*d) + e]*(Sqrt[d] -
I*Sqrt[e]*x))])/(d*Sqrt[-(c^2*d) + e]) + (b*Sqrt[e]*Log[((4*I)*(d*e + c*d*Sqrt[e]*(I*c*Sqrt[d] + Sqrt[-(c^2*d)
+ e]*Sqrt[1 + 1/(c^2*x^2)])*x))/(b*Sqrt[-(c^2*d) + e]*(Sqrt[d] + I*Sqrt[e]*x))])/(d*Sqrt[-(c^2*d) + e]))/e

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fricas [B]  time = 0.94, size = 615, normalized size = 4.42 \[ \left [-\frac {2 \, a c^{2} d^{2} - 2 \, a d e + \sqrt {-c^{2} d e + e^{2}} {\left (b e x^{2} + b d\right )} \log \left (\frac {c^{2} e x^{2} - c^{2} d - 2 \, \sqrt {-c^{2} d e + e^{2}} c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} + 2 \, e}{e x^{2} + d}\right ) - 2 \, {\left (b c^{2} d^{2} - b d e + {\left (b c^{2} d e - b e^{2}\right )} x^{2}\right )} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x + 1\right ) + 2 \, {\left (b c^{2} d^{2} - b d e + {\left (b c^{2} d e - b e^{2}\right )} x^{2}\right )} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x - 1\right ) + 2 \, {\left (b c^{2} d^{2} - b d e\right )} \log \left (\frac {c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} + 1}{c x}\right )}{4 \, {\left (c^{2} d^{3} e - d^{2} e^{2} + {\left (c^{2} d^{2} e^{2} - d e^{3}\right )} x^{2}\right )}}, -\frac {a c^{2} d^{2} - a d e + \sqrt {c^{2} d e - e^{2}} {\left (b e x^{2} + b d\right )} \arctan \left (-\frac {\sqrt {c^{2} d e - e^{2}} c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}}}{c^{2} d - e}\right ) - {\left (b c^{2} d^{2} - b d e + {\left (b c^{2} d e - b e^{2}\right )} x^{2}\right )} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x + 1\right ) + {\left (b c^{2} d^{2} - b d e + {\left (b c^{2} d e - b e^{2}\right )} x^{2}\right )} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x - 1\right ) + {\left (b c^{2} d^{2} - b d e\right )} \log \left (\frac {c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} + 1}{c x}\right )}{2 \, {\left (c^{2} d^{3} e - d^{2} e^{2} + {\left (c^{2} d^{2} e^{2} - d e^{3}\right )} x^{2}\right )}}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccsch(c*x))/(e*x^2+d)^2,x, algorithm="fricas")

[Out]

[-1/4*(2*a*c^2*d^2 - 2*a*d*e + sqrt(-c^2*d*e + e^2)*(b*e*x^2 + b*d)*log((c^2*e*x^2 - c^2*d - 2*sqrt(-c^2*d*e +
e^2)*c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) + 2*e)/(e*x^2 + d)) - 2*(b*c^2*d^2 - b*d*e + (b*c^2*d*e - b*e^2)*x^2)*
log(c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) - c*x + 1) + 2*(b*c^2*d^2 - b*d*e + (b*c^2*d*e - b*e^2)*x^2)*log(c*x*sqr
t((c^2*x^2 + 1)/(c^2*x^2)) - c*x - 1) + 2*(b*c^2*d^2 - b*d*e)*log((c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) + 1)/(c*x
)))/(c^2*d^3*e - d^2*e^2 + (c^2*d^2*e^2 - d*e^3)*x^2), -1/2*(a*c^2*d^2 - a*d*e + sqrt(c^2*d*e - e^2)*(b*e*x^2
+ b*d)*arctan(-sqrt(c^2*d*e - e^2)*c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2))/(c^2*d - e)) - (b*c^2*d^2 - b*d*e + (b*c^
2*d*e - b*e^2)*x^2)*log(c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) - c*x + 1) + (b*c^2*d^2 - b*d*e + (b*c^2*d*e - b*e^2
)*x^2)*log(c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) - c*x - 1) + (b*c^2*d^2 - b*d*e)*log((c*x*sqrt((c^2*x^2 + 1)/(c^2
*x^2)) + 1)/(c*x)))/(c^2*d^3*e - d^2*e^2 + (c^2*d^2*e^2 - d*e^3)*x^2)]

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {arcsch}\left (c x\right ) + a\right )} x}{{\left (e x^{2} + d\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccsch(c*x))/(e*x^2+d)^2,x, algorithm="giac")

[Out]

integrate((b*arccsch(c*x) + a)*x/(e*x^2 + d)^2, x)

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maple [B]  time = 0.07, size = 360, normalized size = 2.59 \[ -\frac {c^{2} a}{2 e \left (c^{2} x^{2} e +c^{2} d \right )}-\frac {c^{2} b \,\mathrm {arccsch}\left (c x \right )}{2 e \left (c^{2} x^{2} e +c^{2} d \right )}+\frac {b \sqrt {c^{2} x^{2}+1}\, \arctanh \left (\frac {1}{\sqrt {c^{2} x^{2}+1}}\right )}{2 c e \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, x d}-\frac {b \sqrt {c^{2} x^{2}+1}\, \ln \left (-\frac {2 \left (\sqrt {c^{2} x^{2}+1}\, \sqrt {-\frac {c^{2} d -e}{e}}\, e +\sqrt {-c^{2} d e}\, c x +e \right )}{-c x e +\sqrt {-c^{2} d e}}\right )}{4 c e \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, x d \sqrt {-\frac {c^{2} d -e}{e}}}-\frac {b \sqrt {c^{2} x^{2}+1}\, \ln \left (-\frac {2 \left (-\sqrt {c^{2} x^{2}+1}\, \sqrt {-\frac {c^{2} d -e}{e}}\, e +\sqrt {-c^{2} d e}\, c x -e \right )}{c x e +\sqrt {-c^{2} d e}}\right )}{4 c e \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, x d \sqrt {-\frac {c^{2} d -e}{e}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a+b*arccsch(c*x))/(e*x^2+d)^2,x)

[Out]

-1/2*c^2*a/e/(c^2*e*x^2+c^2*d)-1/2*c^2*b/e/(c^2*e*x^2+c^2*d)*arccsch(c*x)+1/2/c*b/e*(c^2*x^2+1)^(1/2)/((c^2*x^
2+1)/c^2/x^2)^(1/2)/x/d*arctanh(1/(c^2*x^2+1)^(1/2))-1/4/c*b/e*(c^2*x^2+1)^(1/2)/((c^2*x^2+1)/c^2/x^2)^(1/2)/x
/d/(-(c^2*d-e)/e)^(1/2)*ln(-2*((c^2*x^2+1)^(1/2)*(-(c^2*d-e)/e)^(1/2)*e+(-c^2*d*e)^(1/2)*c*x+e)/(-c*x*e+(-c^2*
d*e)^(1/2)))-1/4/c*b/e*(c^2*x^2+1)^(1/2)/((c^2*x^2+1)/c^2/x^2)^(1/2)/x/d/(-(c^2*d-e)/e)^(1/2)*ln(-2*(-(c^2*x^2
+1)^(1/2)*(-(c^2*d-e)/e)^(1/2)*e+(-c^2*d*e)^(1/2)*c*x-e)/(c*x*e+(-c^2*d*e)^(1/2)))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{4} \, {\left (4 \, c^{2} \int \frac {x}{2 \, {\left (c^{2} e^{2} x^{4} + {\left (c^{2} d e + e^{2}\right )} x^{2} + d e + {\left (c^{2} e^{2} x^{4} + {\left (c^{2} d e + e^{2}\right )} x^{2} + d e\right )} \sqrt {c^{2} x^{2} + 1}\right )}}\,{d x} - \frac {2 \, c^{2} d^{2} \log \relax (c) - 2 \, {\left (c^{2} d e - e^{2}\right )} x^{2} \log \relax (x) - 2 \, d e \log \relax (c) + {\left (c^{2} d e x^{2} + c^{2} d^{2}\right )} \log \left (c^{2} x^{2} + 1\right ) - 2 \, {\left (c^{2} d^{2} - d e\right )} \log \left (\sqrt {c^{2} x^{2} + 1} + 1\right )}{c^{2} d^{3} e - d^{2} e^{2} + {\left (c^{2} d^{2} e^{2} - d e^{3}\right )} x^{2}} + \frac {\log \left (e x^{2} + d\right )}{c^{2} d^{2} - d e}\right )} b - \frac {a}{2 \, {\left (e^{2} x^{2} + d e\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccsch(c*x))/(e*x^2+d)^2,x, algorithm="maxima")

[Out]

-1/4*(4*c^2*integrate(1/2*x/(c^2*e^2*x^4 + (c^2*d*e + e^2)*x^2 + d*e + (c^2*e^2*x^4 + (c^2*d*e + e^2)*x^2 + d*
e)*sqrt(c^2*x^2 + 1)), x) - (2*c^2*d^2*log(c) - 2*(c^2*d*e - e^2)*x^2*log(x) - 2*d*e*log(c) + (c^2*d*e*x^2 + c
^2*d^2)*log(c^2*x^2 + 1) - 2*(c^2*d^2 - d*e)*log(sqrt(c^2*x^2 + 1) + 1))/(c^2*d^3*e - d^2*e^2 + (c^2*d^2*e^2 -
d*e^3)*x^2) + log(e*x^2 + d)/(c^2*d^2 - d*e))*b - 1/2*a/(e^2*x^2 + d*e)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right )}{{\left (e\,x^2+d\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x*(a + b*asinh(1/(c*x))))/(d + e*x^2)^2,x)

[Out]

int((x*(a + b*asinh(1/(c*x))))/(d + e*x^2)^2, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*acsch(c*x))/(e*x**2+d)**2,x)

[Out]

Timed out

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